0=3x^2+14x+8

Solution for 0=3x^2+14x+8 equation:

0=3x^2+14x+8

We move all terms to the left:

0-(3x^2+14x+8)=0

We add all the numbers together, and all the variables

-(3x^2+14x+8)=0

We get rid of parentheses

-3x^2-14x-8=0

a = -3; b = -14; c = -8;
Δ = b2-4ac
Δ = -142-4·(-3)·(-8)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-10}{2*-3}=\frac{4}{-6}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+10}{2*-3}=\frac{24}{-6}
=-4
$